(2x-3)^2=441和8(x-1)^3=125的过程
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(2x-3)^2=441和8(x-1)^3=125的过程
(2x-3)^2=441和8(x-1)^3=125的过程
(2x-3)^2=441和8(x-1)^3=125的过程
(2x-3)²=441
(2x-3)²=21²
2x-3=±21
2x=3±21
x=(3±21)/2
∴X1=12
X2=-9
8(x-1)³=125
[2(x-1)]³=5³
2(x-1)=5
x-1=2.5
x=3.5
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