/>
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/29 10:17:46
/>
/>
/>
t= √2 (√2/2 sinx+√2/2cosx) = √2 sin(x+45°)
- √2≤t≤√2
(2)
f(x)=t+m/2 [ (sinx+ cosx )^2-1]
=t+m/2( t^2-1)
=m/2( t^2 +2/m t-1)
=m/2( t +1/m)^2 - m/2*1/m^2
=m/2( t +1/m)^2 ...
全部展开
t= √2 (√2/2 sinx+√2/2cosx) = √2 sin(x+45°)
- √2≤t≤√2
(2)
f(x)=t+m/2 [ (sinx+ cosx )^2-1]
=t+m/2( t^2-1)
=m/2( t^2 +2/m t-1)
=m/2( t +1/m)^2 - m/2*1/m^2
=m/2( t +1/m)^2 - 1 /2m
m≤ - √2/2 或 m ≥ √2/2时
f(x)的最小值为- 1 /2m
- √2/2≤m≤0 时
t= √2,f(x)的最小值为√2+m/2
0≤m≤√2/2时
t= - √2, f(x)的最小值为- √2+m/2
收起