作业帮[(a^2+3)/(a^2-1)]-[(a+1)/(a-1)]+1
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/05 21:48:44
[(a^2+3)/(a^2-1)]-[(a+1)/(a-1)]+1
[(a^2+3)/(a^2-1)]-[(a+1)/(a-1)]+1
[(a^2+3)/(a^2-1)]-[(a+1)/(a-1)]+1
解:由题可得:
[(a^2+3)/(a^2-1)]-[(a+1)/(a-1)]+1
=(a^2+3)/(a+1)(a-1) - (a+1)^2/(a+1)(a-1) +(a+1)(a-1)/(a+1)(a-1)
=[a^2+3-(a^2+2a+1)+(a+1)(a-1)]/(a+1)(a-1)
=(a^2+3-a^2-2a-1+a^2-1)/(a+1)(a-1)
=(a^2-2a+1)/(a+1)(a-1)
=(a-1)(a-1)/(a+1)(a-1)
=(a-1)/(a+1)
简单你留著自己做咯……
原式=[(a^2+3)/(a^2-1)]-[(a+1)^2/(a^2-1)]+1
=[(a^2+3-a^2-2a-1)/(a^2-1)]+1
=(-2a+2a)/[(a+1)(a-1)]+1
=[-2(a+1)]/[(a+1)(a-1)]+1
=-2/(a-1)+(a-1)/(a-1)
=(a-3)/(a-1)
(a 1)(a 2)(a 3)(a
(a+2)(a+1)-a(a-3)
a(a-1)(a-2)(a-3)(a-4)因式分解
【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a－a a=[ ] [4]a－a=a＋a a=[ ]
(通分） a/a^a^a+3a+2 ,a/a^a+2a+1 ,-1/3a+6
（a-a/a+1)/(a*a-2a)*(a+1)/(a*a+3a+2)要详细的计算说明！
a+a+1+a+2+a+3+a+4+a+5+a+6+a+7.+a+2013+a+2014=?
幂的计算题1、a×a^2×a^3×a^4×a^52、a+2a+3a+4a+a×a^2×a^3×a^4
[a^2-4/(a-3)(a+2)+(a+2)/a-3]除以a+1/a-3
[a/(a-1)+a/(a+2)](a+2)/(2a平方+3a+1)化简
(a+1/a方-a+4/1-a方)/a方+2a-3/a+3
求和：1/a+2/a^a+3/a*a*a+...+n/a的n次方
已知a×a+a-1=0求a*a*a+2a+3
a=-1 求a-2a+3a-4a+5a-6a+...+99a-100a
因式分解 a^3+a^2-a-1
(a+1)(a+2)(a-3)计算
1A,2A,3A...
1A,2A,3A...