x²+9x/x²+3x+x²-9/x²+6x=9

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x²+9x/x²+3x+x²-9/x²+6x=9
x²+9x/x²+3x+x²-9/x²+6x=9

x²+9x/x²+3x+x²-9/x²+6x=9
x²+9x/x²+3x + x²-9/x²+6x+9 = (x²+9x)/x(x+3)+(x+3)(x-3)/(x+3)² =(x²+9x) /x(x+3)+(x-3)/(x+3) =(x²+9x+x²-3x)/x(x+3) =(2x²+6x)/x(x+3) =2x(x+3)/x(x+3) =2