:x^2+y^2-xy+x-1/2y+1/4=0 求X,Y的值
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:x^2+y^2-xy+x-1/2y+1/4=0 求X,Y的值
:x^2+y^2-xy+x-1/2y+1/4=0 求X,Y的值
:x^2+y^2-xy+x-1/2y+1/4=0 求X,Y的值
两边乘以2,得:
2x²+2y²-2xy+x+y+(1/2)=0
(x²-2xy+y²)+[x²+x+(1/4)]+[y²+y+(1/4)]=0
(x-y)²+[x+(1/2)]²+[y+(1/2)]²=0
则:
x=-1/2
y=-1/2
【原题的符号可能还有问题,给出的解答已经更新了符号】
x^2+y^2-xy+x-1/2y+1/4=0
通分同乘4,得:
[4x²+4y²-4xy+4x-2y+1]/4=0
对分子而言:(4x²-4xy+y²)+2(2x-y)+1+3y²=0
(2x-y)²+2(2x-y)+1+3y²=0
(2x-y+1)²+3y²=0
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x^2+y^2-xy+x-1/2y+1/4=0
通分同乘4,得:
[4x²+4y²-4xy+4x-2y+1]/4=0
对分子而言:(4x²-4xy+y²)+2(2x-y)+1+3y²=0
(2x-y)²+2(2x-y)+1+3y²=0
(2x-y+1)²+3y²=0
则:
x=-1/2
y=0
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