(m+n-p)^2-(m-n-p)^2因式分解大神们帮帮忙
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(m+n-p)^2-(m-n-p)^2因式分解大神们帮帮忙
(m+n-p)^2-(m-n-p)^2因式分解大神们帮帮忙
(m+n-p)^2-(m-n-p)^2因式分解大神们帮帮忙
将m-p看成一个整体
(m+n-p)^2-(m-n-p)^2 =(m+n-p+m-n-p)(m+n-p-m+n+p) =(2m-2p)*2n =4n(m-p)
(m-2n-p)(m-2n+p)-(m+2n+p)(m+2n+p)
化简,1.[(m+n-p)(m+p+n)-(m+n)²]/(-p),2.[(m+n)(m-n)-(m-n)²+2n(m-n)]/4n
化简(-m+2n-p)(-p-2n+m)
(2m+n-p)(2m-n+p)
(2m+n-p)(2m-n-p)等于什么
(2m+n-p)( 2m+p-n)
(m-2n-p)(-m-2n-p)
化简:(2m+n-p)*(2m-n+p)
(-2m-3n-p)(2m-3n-p)
(m-2n+3p)(m+3n+3p)
因式分解:(m-n)(p-q)-(n-m)^2(q-p)
(2m+n-p)²
m-(2m-n-p)=
(m+n)-( )=2m-p
(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
已知m、n、p满足|2m|+m=0,|n|=n,p|p|=1.化简:|n|-|m-p-1|+|p+n|-|2n+1|.已知m、n、p满足|2m|+m=0,|n|=n,p|p|=1.化简:|n|-|m-p-1|+|p+n|-|2n+1|.
n/m与2n+q/m+p,怎么通分
已知m、n、p满足/2m/+m=0,/n/=n,p/p/=1,化简/n/-/m-p-1/-/2n+1/.