用换元法求f(x)=4x-3/x^2-1的值域怎么做?就是设4x-3=t，之后怎么做呢

f(x+1)+f(x-1)=4x^3-2x求f(x) 函数f(x)={(1/2)^x,(x>4),f(x+3),(x 函数f(x)={(1/2)^x,(x>4),f(x+3),(x 设函数f(x)={(1/2)^x(x≥4),f(x+3)(x 数学f(x)=x(x+1)(x+2)(x+3)(x+4)(x+5),求f'(0)=? f(x)=x(x-1)(x+2)(x-3)(x+4)……(x+100),求f'(1) 已知f(x)=x(x-1)(x-2)(x-3)(x-4)(x-5),则f‘(0)为 设函数f(x)=(1/2）^x(x≥4), f(x)=f(x+3)(x 已知f(x)满足2f(x)+f(1/x)=3x,求f(x) F(X)满足F(x)+2f(x分之1)=3X,求f(x) 已知f(x)满足2f(x)+f(1/x)=3x,求f(x)? 已知f(x)满足2f(x)+f(-x)=-3x+1,求f(x) 已知f(x)满足f(x)+2f(1/x)=3x,求f(x) , 2f(x)+f(1/x)=3x-4,求f(x)的解析式 已知3f(x)+2f(1/x)=4x,求f(x) 3f(x)+2f(1/x)=4x,求f(x)的解析式 设f(x)满足3f(x)+2f(1/x)=4x,则f(x)=＿＿. 若函数f(x)满足3f(x)+2f(-1/x)=4x,求f(x)