-1/x+1/x(x+1)+1/(x+1)(x+2)+……+1/(x+2009)(x+2010)=1
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-1/x+1/x(x+1)+1/(x+1)(x+2)+……+1/(x+2009)(x+2010)=1
-1/x+1/x(x+1)+1/(x+1)(x+2)+……+1/(x+2009)(x+2010)=1
-1/x+1/x(x+1)+1/(x+1)(x+2)+……+1/(x+2009)(x+2010)=1
有这么一个式子:1/n(n+1) = 1/n - 1/(n+1);;
那么你的式子中除了第一项外都可以 写成上面的形式...如:
1/x(x+1) = 1/x - 1/(x+1);
1/(x+1)(x+2) = 1/(x+1) - 1/(x+2)
1/(x+2009)(x+2010) = 1/(x+2009) - 1/(x+2010)
再将所有式子想加,都可以抵消,只剩下一项了 -1/(x+2010) = 1 ,求出 x = -2011
sb吾问无为谓我我我我WWW
x/x+(1-x)/x-1/x
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/X-3/-/X-1/