(2ab)^2*(a^2-b^2)-(2a^2b^2)^2/(4a^2)+4a^2b^4
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/31 06:37:00
(2ab)^2*(a^2-b^2)-(2a^2b^2)^2/(4a^2)+4a^2b^4
(2ab)^2*(a^2-b^2)-(2a^2b^2)^2/(4a^2)+4a^2b^4
(2ab)^2*(a^2-b^2)-(2a^2b^2)^2/(4a^2)+4a^2b^4
(2ab)^2×(a^2-b^2)-(2a^2b^2)^2/(4a^2)+4a^2b^4 =4a^2b^2×(a^2-b^2)-4a^4b^4/(4a^2)+4a^2b^4 =4a^2[b^2×(a^2-b^2)-b^4]/(4a^2)+4a^2b^4 =b^2×(a^2-b^2)-b^4+4a^2b^4 =a^2b^2-b^4-b^4+4a^2b^4 =a^2b^2-2b^4+4a^2b^4
a+b/2ab
2AB/A+B
a+b/2ab
(a-b)^2/ab-(a^2-b^2)/ab
(ab(a^-2ab)-a^2b(a-3b))÷(3a^b)
3(-ab+2a)-(3a-b)+3ab
b/(a^2-ab)+c/(b^2-ab)+(a+b^2)/(a^2b-ab^2)
(a-b)平方-2ab(b-a)
(a-b)^3+2ab(a-b)
[(a^2-2ab)/-ab+b^2]/[(a/a+b)/(2ab/2b-a)]
(a+2根号ab+b)/(a-b) 减去 {[根号a/(a+根号ab)减去 根号b/(b-根号ab)]}除以根号a/(b+根号ab)
计算:a+2根号(ab+b/a-b)-【(根号a/a+根号ab)-(根号b/b-根号ab)】除以根号a/b+根号ab明天要交
(a+b-2ab)(a+b-2)+(1-ab)^2
(a+ab)-[(ab-2b)-a]-(-9ab),其中a+b=-7,ab=3.
因式分解ab(ab+1)^2-ab(a+b)-a-b+1 急求!
求证:A/(AB+B^2)-B/(AB+A^2)=1/B-1/A
化简:(a/b-b/a)/【(a²-2ab+b²)/ab】的结果是
a>2,b>2ab