lim(1+1/n)^n+1/2011=n趋向无群大lim(1+1/n)^(n+1/2011)= n趋向无穷大
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lim(1+1/n)^n+1/2011=n趋向无群大lim(1+1/n)^(n+1/2011)= n趋向无穷大
lim(1+1/n)^n+1/2011=
n趋向无群大
lim(1+1/n)^(n+1/2011)= n趋向无穷大
lim(1+1/n)^n+1/2011=n趋向无群大lim(1+1/n)^(n+1/2011)= n趋向无穷大
lim(n→∞)(1+1/n)^(n+1/2011)
=lim(n→∞)(1+1/n)^n*lim(n→∞)(1+1/n)^(1/2011)
=e
由几何平均≤算术平均,得 x(n 1)≤√a.即该数列有界。再证单调性, x(n 1)≥x(n)即单调增。于是xn收敛。 n趋近正无穷时,x(n 1)=x(n)=
这哥是欧拉常数嘛?
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