观察下列等式:1/(1*2)=1-1/2 ,1/(2*3)=1/2-1/3 ,1/(3*4)=1/3-1/4将以上三个等式两边分别相加得:1/(1*2)+ 1/(2*3)+1/(3*4)=1-1/2 +1/2-1/3 +1/3-1/4=3/4(1)猜想并写出:1/(n*n+1)=__________________(2
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观察下列等式:1/(1*2)=1-1/2 ,1/(2*3)=1/2-1/3 ,1/(3*4)=1/3-1/4将以上三个等式两边分别相加得:1/(1*2)+ 1/(2*3)+1/(3*4)=1-1/2 +1/2-1/3 +1/3-1/4=3/4(1)猜想并写出:1/(n*n+1)=__________________(2
观察下列等式:1/(1*2)=1-1/2 ,1/(2*3)=1/2-1/3 ,1/(3*4)=1/3-1/4
将以上三个等式两边分别相加得:
1/(1*2)+ 1/(2*3)+1/(3*4)=1-1/2 +1/2-1/3 +1/3-1/4=3/4
(1)猜想并写出:1/(n*n+1)=__________________
(2)直接写出下列各式的计算结果:
①1/(1*2)=1/(2*3)+1/(3*4)+……+1/(2008*2009)=_____________
②1/(1*2)=1/(2*3)+1/(3*4)+……+1/(n*n+1)=_________________
(3)探究并计算:
1/(2*4)+1/(4*6)+1/(6*8)+……+1/(2008*2010)=
⊙ o ⊙ 打得我手都酸了~
观察下列等式:1/(1*2)=1-1/2 ,1/(2*3)=1/2-1/3 ,1/(3*4)=1/3-1/4将以上三个等式两边分别相加得:1/(1*2)+ 1/(2*3)+1/(3*4)=1-1/2 +1/2-1/3 +1/3-1/4=3/4(1)猜想并写出:1/(n*n+1)=__________________(2
1/n-1/(n+1)
2008/2009 1-1/(n+1)
把每一个都先乘以4就和原来一样了答案是2009/8040