(x-1/2)(2x+1)(2x²+1/2)除以(16x的四次方-1)等于几
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/01 16:16:11
(x-1/2)(2x+1)(2x²+1/2)除以(16x的四次方-1)等于几
(x-1/2)(2x+1)(2x²+1/2)除以(16x的四次方-1)等于几
(x-1/2)(2x+1)(2x²+1/2)除以(16x的四次方-1)等于几
原式=1/4*(2x-1)(2x+1)/(4x²+1)/(16x^4-1)
=1/4*(4x²-1)/(4x²+1)/(16x^4-1)
=1/4*(16x^4-1)/(16x^4-1)
=1/4
原式=1/4*(2x-1)(2x+1)(4x²+1)/(4x²+1)/(16x^4-1)
=1/4*(4x²-1)/(4x²+1)/(16x^4-1)
=1/4*(16x^4-1)/(16x^4-1)
=1/4