2x-3y=5 5y-3x=6
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2x-3y=5 5y-3x=6
2x-3y=5 5y-3x=6
2x-3y=5 5y-3x=6
2x-3y=5. 5y-3x=6
6X-9Y=15.10Y-6X=12
解:Y=27
X=43
x+y/2+x-y/6=5 2(x+y)-3(x-y)=-2
6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
(x+y-5)*(x+y-5)+(x-y+3)=0 x*x-y*y
已知:3x-5y=0,求x/y,x-y/y,x-y/x
3x+5y-(x+y)=6 2(x+y)-3x=-7
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)=3(x-y)²-4(x-y)+7(x-y)-6(x-y)²=
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
把(x-y)看做一个整体,合并同类项5(x-y)+2(x-y)-4(x-y)=3(x-y)次方-4(x-y)+7(x-y)-6(x-y)次方=
4x-2y-6y*-y-3x+5y* *=2 就是平方
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
x+y/2+x-y/3=5/6;x=y/6-x-y/3=1/2