1*3/1+3*5/1+5*7/1+7*9/1+...+2003*2005/1 怎么算?
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1*3/1+3*5/1+5*7/1+7*9/1+...+2003*2005/1 怎么算?
1*3/1+3*5/1+5*7/1+7*9/1+...+2003*2005/1 怎么算?
1*3/1+3*5/1+5*7/1+7*9/1+...+2003*2005/1 怎么算?
1/[(2n-1)*(2n+1)]=[1/(2n-1)-1/(2n+1)]/2
数列求和中的裂项相消法的应用
1*3/1+3*5/1+5*7/1+7*9/1+...+2003*2005/1=[1-1/3+1/3-1/5+...+1/2003-1/2005]/2=1002/2005
1-3+5-7+...
(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7) 简算(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7) 简便计算
(1/3+1/5+1/7)*(1/5+1/7+1/9)-(1/3+1/5+1/7+1/9)*(1/5+1/7)=?
1,3,5,7,9.
化简5/7:1/3
7/3*[7/5-(7/3+5/1)]简便算法
1/1*3+1/1*3*5+1/1*3*5*7+1/1*3*5*7*9-73/945
1/1*3*5+1/3*5*7+1/5*7*9.+1/95*97*99
1/1×3+1/3×5+1/5×7+1/7×9.+1/2011×2013
简算:1/1*3+1/3*5+1/5*7+1/7*9+1/9*11
1/1*3+1/3*5+1/5*7+1/7*9+...1/17*19=
计算1/(1×3)+1/(3×5)+1/(5×7)+1/(7×9)+.+1/(19×21)
1/1×3+1/3×5+1/5×7+1/7×9+.+1/2013×2015
1/1*3+1/3*5+1/5*7+1/7*9+.+1/101*103
帮帮忙1/1*3+1/3*5+1/5*7+1/7*9+...1/99*101
1/1*3+1/3*5+1/5*7+1/7*9+1/49*51=
计算:1/1×3+1/3×5+1/5×7+1/7×9``````+1/2001×2003
(1*3)/1+(3*5)/1+(5*7)/1+(7*9)/1+(9*11)/1