已知数列{An}满足A1=1,An+1={1/2An+n-1,n为奇数,An-2n,n为偶数},记Bn=A2nn∈N*求数列{Bn}的通项公式（提示：Bn+1=A2（n+1）=A（2n+1）+1）设Cn=（2^2n-1 -1）Bn²,数列{Cn}的前n项和为Sn,若对任意n属于N*,不等式

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