解这个方程急!x+(x+1)(x+2)+(x+3)=58我是小学大哥哥，大姐姐们········

解这个方程急!x+(x+1)(x+2)+(x+3)=58我是小学大哥哥，大姐姐们········
解这个方程急!x+(x+1)(x+2)+(x+3)=58
我是小学大哥哥，大姐姐们········

解这个方程急!x+(x+1)(x+2)+(x+3)=58我是小学大哥哥，大姐姐们········
方程化为：x^3+6x^2+12x-52=0
公式法解得
X1=1.91486764116886
X2=-3.95743382058443-3.3903748297059i
X3=-3.95743382058443+3.3903748297059i

x+(x+1)(x+2)+(x+3)= x + x² +3x + 2 + x + 3
= x² +5x + 5 = 58
=>
x² + 5x -53 = 0
根据求根公式得到
x = 1/2 *(-5 ± 根号(237))

x^2+5x+5=58
x^2+5x-53=0
x= 1/2 *(-5 ± 根号(237))

用配方法吧
x+x2+3x+2+x+3=58
x2+5x+5=58
x2+2*5/2*x+25/4-25/4+5=58
(x+5/2)(x+5/2)-5/4=58
(x+5/2)(x+5/2)=58+5/4
x+5/2=±√237/4
x=±1/2√237-5/2