已知|x+2|+（y+3）²＝0,求6xy²-[3x²y-（2x²y-xy²）]的值.

已知|x+2|+（y+3）²＝0,求6xy²-[3x²y-（2x²y-xy²）]的值.
已知|x+2|+（y+3）²＝0,求6xy²-[3x²y-（2x²y-xy²）]的值.

已知|x+2|+（y+3）²＝0,求6xy²-[3x²y-（2x²y-xy²）]的值.

x=-2 y=-3
6xy²-3x²y+2x²y-xy²
=-x²y+5xy²
=xy(-x+5y)
=-78