若|x+(-2)|+|y+3|+|z|=0,求x+y+z的值
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若|x+(-2)|+|y+3|+|z|=0,求x+y+z的值
若|x+(-2)|+|y+3|+|z|=0,求x+y+z的值
若|x+(-2)|+|y+3|+|z|=0,求x+y+z的值
因为|x+(-2)|>=0,|y+3|>=0,|z|>=0,所以x=2,y=-3,z=0,所以x+y+z=-1
|x+(-2)|=0 x=2
|y+3| y=-3
|z|=0 z=0
x+y+z=-1
由题意可知,X=2,Y=-3,Z=0,所以X+Y+Z=-1
解
/x-2/≥0
/y+3/≥0
/z/≥0
要使式子相加为0
只能
x-2=0
y+3=0
z=0
∴x=2,y=-3,z=0
∴x+y+z
=2-3+0
=-1
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