y=x^2-4x-5/x^2-3x-4值域是不等于1且不等于6/5，

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y=x^2-4x-5/x^2-3x-4值域是不等于1且不等于6/5，
y=x^2-4x-5/x^2-3x-4值域
是不等于1且不等于6/5，

y=x^2-4x-5/x^2-3x-4值域是不等于1且不等于6/5，
y=x^2-4x-5/x^2-3x-4
=[(x+1)(x-5)]/[(x+1)(x-4)]
则[(x+1)(x-4)]不等于0
则x+1不等于0且x-4不等于0
x不等于-1且x不等于4
又y=[(x+1)(x-5)]/[(x+1)(x-4)]
=(x-5)/(x-4)
=[(x-4)-1]/(x-4)
=1-[1/(x-4)]
由x不等于4,则1/(x-4)不等于0
则y=1-[1/(x-4)]不等于1
又x不等于-1 则代入得y不等于6/5
则值域为{y|y不等于6/5且y不等于1}

y=(x^2-4x-5)/(x^2-3x-4)
=(x+1)(x-5)/(x+1)(x-4)
=[(x-4)-1]/(x-4)
=1-1/(x-4) (x不等于4)
y的值域为（负无穷，1）并（1，正无穷）

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