已知2x-2y-5=1,求[2(x-y)^2-3(x-y)]÷(y-x)的值
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已知2x-2y-5=1,求[2(x-y)^2-3(x-y)]÷(y-x)的值
已知2x-2y-5=1,求[2(x-y)^2-3(x-y)]÷(y-x)的值
已知2x-2y-5=1,求[2(x-y)^2-3(x-y)]÷(y-x)的值
[2(x-y)²-3(x-y)]÷(y-x)
=[2(y-x)²+3(y-x)]÷(y-x)
=2(y-x)+3
=2y-2x+3
已知2x-2y-5=1
得:2y-2x=-5-1=-6
所以原式=-6+3=-3
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