已知f(x)=sin(2x+л/3)+sin(2x-л/3) g(x)=根号三cos2x (1)设已知f(x)=sin(2x+л/3)+sin(2x-л/3) g(x)=根号三cos2x(1)设h(x)=f(x)g(x)求h(x)单调递增区间

已知f(x)=sin(2x+л/3)+sin(2x-л/3) g(x)=根号三cos2x (1)设已知f(x)=sin(2x+л/3)+sin(2x-л/3) g(x)=根号三cos2x(1)设h(x)=f(x)g(x)求h(x)单调递增区间
已知f(x)=sin(2x+л/3)+sin(2x-л/3) g(x)=根号三cos2x (1)设
已知f(x)=sin(2x+л/3)+sin(2x-л/3) g(x)=根号三cos2x
(1)设h(x)=f(x)g(x)求h(x)单调递增区间

已知f(x)=sin(2x+л/3)+sin(2x-л/3) g(x)=根号三cos2x (1)设已知f(x)=sin(2x+л/3)+sin(2x-л/3) g(x)=根号三cos2x(1)设h(x)=f(x)g(x)求h(x)单调递增区间
f(x)=sin(2x＋π3)＋sin(2x－π/3)
f(x)=sin(2x)cos(π/3)＋co(2x)sin(π/3)＋sin(2x)cos(π/3)－cos(2x)sin(π/3)
f(x)=2sin(2x)cos(π/3)
f(x)=√3sin(2x)
g(x)=√3cos2x
则：
h(x)=f(x)g(x)=3sin(2x)cos(2x)
h(x)=(3/2)sin(4x)
函数h(x)的递增区间是：
2kπ－π/2≤4x≤2kπ＋π/2
得：
(1/2)kπ－(π/8)≤x≤(1/2)kπ＋(π/8)
递增区间是：[(1/2)kπ－(π/8),(1/2)kπ＋(π/8)],其中k∈Z