解二元一次方程y/3-(x+1)/6=3 (x-3)/4-(y-3)/3=1/6

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解二元一次方程y/3-(x+1)/6=3 (x-3)/4-(y-3)/3=1/6
解二元一次方程y/3-(x+1)/6=3 (x-3)/4-(y-3)/3=1/6

解二元一次方程y/3-(x+1)/6=3 (x-3)/4-(y-3)/3=1/6
2y-x-1=18
3x-9-4y+12=2
=>
2y-x=19(1)
-4y+3x=-1(2)
(1)*2+(2)得
x=37
y=28

(1)式两边同乘于6得 2y - x - 1 = 18,2y -x = 19 (3)
(2)式两边同乘于12得:3x-9 - 4y + 12 = 2,3x - 4y = -10 (4)
(3)× 2 + (4)得
4y-2x + 3x-4y = 38 - 10
x = 28,代入(3)得
2y - 28 = 19
y=47/2