3x+4y=18,2x-3y=-5先到先得
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3x+4y=18,2x-3y=-5先到先得
3x+4y=18,2x-3y=-5
先到先得
3x+4y=18,2x-3y=-5先到先得
3x+4y=18.(1)
2x-3y=-5.(2)
(1)*3+(2)*4得
17x=34
x=2
代入(1)得
6+4y=18
4y=12
y=3
解得
x=2
y=3
3x+4y=18............1
2x-3y=-5..................2
1式*3+2式*4得
17x=34
x=2
将x=2代入1式得
3*2+4y=18
4y=12
y=3
x=2 y=3
方程一*2
方程二*3
之后相减去掉x得y=3
带入得x=2
3x+4y=18......(1)
2x-3y=-5.......(2)
(1)*3+(2)*4,17x=34
x=2
代入(1)3*2+4y=18,4y=12
y=3
x=2,y=3
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
3X=5Y (X+Y)*3X=(2Y+X)*4+2*2
(x+y-5)*(x+y-5)+(x-y+3)=0 x*x-y*y
已知:3x-5y=0,求x/y,x-y/y,x-y/x
(5x+3y)(3y-5x)-(4x-y)(4y+x)=
2(x+y)-3(x-y)=3 ,4(x+y)+3(x-y)=15
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
3(x+y)-2(x-y)=11 4(x+y)+3(x-y)=9
x+y/2+x-y/6=5 2(x+y)-3(x-y)=-2