已知R上的函数f(x)=1/3ax3+1/2bx2+cx在x=1时取得最值,且y=f(x)图像上有一点处得切线斜率为-a(1)求证0《b/a
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已知R上的函数f(x)=1/3ax3+1/2bx2+cx在x=1时取得最值,且y=f(x)图像上有一点处得切线斜率为-a(1)求证0《b/a
已知R上的函数f(x)=1/3ax3+1/2bx2+cx在x=1时取得最值,且y=f(x)图像上有一点处得切线斜率为-a
(1)求证0《b/a
已知R上的函数f(x)=1/3ax3+1/2bx2+cx在x=1时取得最值,且y=f(x)图像上有一点处得切线斜率为-a(1)求证0《b/a
Lucero 's three daughters from childhood by his father from captivity and sexual abuse. He gave birth to a daughter and 7 children . ,mac cosmetics brushes
British The three daughters were the local police custody.
Lucero local officials are waiting for the results of psychological identification . He could face up to 50 years in prison.
Xinhua News Agency May 28 deoxyribonucleic acid (DNA) test results showed a 67- year-old man in Argentina is one of his daughter,Oakley sunglasses, the father of 7 children born .