已知x/2=y/3=z/5,且3x+4z-2y=40,求x y z的值.

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已知x/2=y/3=z/5,且3x+4z-2y=40,求x y z的值.
已知x/2=y/3=z/5,且3x+4z-2y=40,求x y z的值.

已知x/2=y/3=z/5,且3x+4z-2y=40,求x y z的值.
∵x/2=y/3,∴3x=2y,3x-2y=0
又∵3x+4z-2y=40,∴4z=40,z=10
x/2=z/5,x=4;y/3=z/5,y=6
∴x=4,y=6,z=10

设x=2k y=3k z=5k
3*2k+4*5k-2*3k=40
k=2
所以x=4 y=6 z=10

X/2=Y/3=Z/5得X=2Y/3,Z=5Y/3将其带入3X+4Z-2Y=40得2Y+20Y/3-2Y=40得Y=6,再求得X=4,Z=10