作业帮计算:(x+2)/(x^2 - x - 6) + 2x/(x^2 - 3x) - x/(x^2 - 6x + 9)
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/02 18:39:18
计算:(x+2)/(x^2 - x - 6) + 2x/(x^2 - 3x) - x/(x^2 - 6x + 9)
计算:(x+2)/(x^2 - x - 6) + 2x/(x^2 - 3x) - x/(x^2 - 6x + 9)
计算:(x+2)/(x^2 - x - 6) + 2x/(x^2 - 3x) - x/(x^2 - 6x + 9)
(x+2)/(x^2-x-6)+2x/(x^2-3x)-x/(x^2-6x+9)
=(x+2)/[(x-3)(x+2)]+2x/[x(x-3)]-x/[(x-3)^2]
=1/(x-3)+2/(x-3)-x/[(x-3)^2]
=3(x-3)/[(x-3)^2]-x/[(x-3)^2]
=(3x-9-x)/[(x-3)^2]
=(2x-9)/[(x-3)^2]
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