(x^2-xy)/(xy-y^2)-(y^2+xy)/(x^2+xy)+(x^2+y^2)/xy2.(x-2)/x^2/(1-2/x)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 13:27:44
(x^2-xy)/(xy-y^2)-(y^2+xy)/(x^2+xy)+(x^2+y^2)/xy2.(x-2)/x^2/(1-2/x)
(x^2-xy)/(xy-y^2)-(y^2+xy)/(x^2+xy)+(x^2+y^2)/xy
2.(x-2)/x^2/(1-2/x)
(x^2-xy)/(xy-y^2)-(y^2+xy)/(x^2+xy)+(x^2+y^2)/xy2.(x-2)/x^2/(1-2/x)
(x^2-xy)/(xy-y^2)-(y^2+xy)/(x^2+xy)+(x^2+y^2)/xy
=x(x-y)/(y(x-y))-y(x+y)/(x(x+y))+(x^2+y^2)/xy
=x/y-y/x+(x^2+y^2)/xy
=(x^2-y^2)/xy+(x^2+y^2)/xy
=2x^2/xy
=2x/y
x(x-y)/y(x-y)-y(y+x)/x(x+y)+(x^2+y^2)/xy
=x/y-y/x+(x^2+y^2)/xy
=x^2/xy-y^2/xy+(x^2+y^2)/xy
=(x^2-y^2+x^2+y^2)/xy
=2x^2/xy
=2x/y
(x-2)/x^2/(1-2/x)
=(x-2)/[(x-2)/x]/x^2
=x*(x-2)/(x-2)/x^2
=x/x^2
=1/x
不是因式分解吧?
化简:
(x^2-xy)/(xy-y^2)-(y^2+xy)/(x^2+xy)+(x^2+y^2)/xy
=x(x-y)/[y(x-y)]-y(y+x)/[x(x+y)]+(x²+y²)/(xy)
=x/y-y/x+(x²+y²)/(xy)
=(x²-y²+x²+y²)/(xy)
=2x²/(xy)
=2x/y
我看不懂