已知数列{an}满足a1=0,a2=2,且对任意m'n属于N*,都有a(2m-1)+a(2n+1)=2a(m+n-1)+2(m-n)^2设cn=(a(n+1)-an)q^(n-1),求数列{cn}的前n项和Sn
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已知数列{an}满足a1=0,a2=2,且对任意m'n属于N*,都有a(2m-1)+a(2n+1)=2a(m+n-1)+2(m-n)^2设cn=(a(n+1)-an)q^(n-1),求数列{cn}的前n项和Sn
已知数列{an}满足a1=0,a2=2,且对任意m'n属于N*,都有a(2m-1)+a(2n+1)=2a(m+n-1)+2(m-n)^2
设cn=(a(n+1)-an)q^(n-1),求数列{cn}的前n项和Sn
已知数列{an}满足a1=0,a2=2,且对任意m'n属于N*,都有a(2m-1)+a(2n+1)=2a(m+n-1)+2(m-n)^2设cn=(a(n+1)-an)q^(n-1),求数列{cn}的前n项和Sn
a(2n-1)+a(2n+1)=2a(n+n-1)+0=2a(2n-1),
a(2n+1)=a(2n-1)=...=a(1)=0.
a(2n-1)=0.
a[2(n+1)-1] + a(2n+1) = 2a(n+1 + n-1) + 2(n+1-n)^2,
a(2n+1) + a(2n+1) = 0 = 2a(2n) + 2,
a(2n)=-1, 与a(2)=2矛盾哈.
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