化简求值:[(x+y)(x-2y)-(x+2y)ˆ2]÷1/2y,其中想x=-1,y=1/4
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化简求值:[(x+y)(x-2y)-(x+2y)ˆ2]÷1/2y,其中想x=-1,y=1/4
化简求值:[(x+y)(x-2y)-(x+2y)ˆ2]÷1/2y,其中想x=-1,y=1/4
化简求值:[(x+y)(x-2y)-(x+2y)ˆ2]÷1/2y,其中想x=-1,y=1/4
:[(x+y)(x-2y)-(x+2y)ˆ2]÷1/2y
=(x^2-2xy+xy-2y^2-x^2-4xy-4y^2)*2/y
=(-5xy-6y^2)*2/y
=-10x-12y
将 x=-1,y=1/4代入
有 -10*(-1)-12*1/4=10-3=7
[(x+y)(x-2y)-(x+2y)ˆ2]÷1/2y
=[(x^2-2xy+xy-2y^2)-(x^2+4xy+4y^2)]*2y
=(x^2-2y^2-xy-x^2-4xy-4y^2)*2y
=(-5xy-6y^2)*2y
=-5xy^2-6y^3
=-5*(-1)*1/16-6*1/64
=5/16-3/32
=7/32
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