化简：cos(π-α)·sin(-π-α) / cos(11/2π-β)·tan(3π+β)RT、quickly~

化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α) 化简 1+sin(α-2π)·sin(π+α)-2cos平方(-α)要有过程 [sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简 化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α) (1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 （3/2*π 化简sin(π/4+α)cosα-sin(π/4-α)sinα sin(π-α)=-2sin(π/2+α),求sinα·cosα 2sinα*cosα*cos(2π-α)+cos(π+2α)*cosα*tanα化简! 化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π) 化简[sin(π/2-α）cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π+α) 化简sin(α-2π)+sin(-a-3π)cos(α-3π)/cos(π-α)-cos(-π-α)cos(α-4π) 若cosα>sinα,(-π/2 若（sinα+cosα）/（sinα-cosα）=2 则sin(α-5π)·sin(3π/2-α)=? 化简：cos(π/3+α)+sin(π/6+α) 化简sin(π/4-α)+cos(π/4+α) 化简：2sin（π+α）cos（π-α） 化简sin(nπ+α)/cos(nπ-α) 化简cos(3/2π+π)sin(-π+α)