设Sn是等差数列{an}的前N项和,若S7=35,则a4为几?

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设Sn是等差数列{an}的前N项和,若S7=35,则a4为几?
设Sn是等差数列{an}的前N项和,若S7=35,则a4为几?

设Sn是等差数列{an}的前N项和,若S7=35,则a4为几?
S7=(a1+a7)X7/2
因为是等差数列,所以a1+a7=2a4
(a1+a7=a1+a1+6d=2X(a1+3d)=2a4)
所以S7=7a4=35
a4=5

S7=7a4
所以a4=5

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