x+y=0.2 x+3y=1 求3x²+12xy+12y²的值

x+y=0.2 x+3y=1 求3x²+12xy+12y²的值
x+y=0.2 x+3y=1 求3x²+12xy+12y²的值

x+y=0.2 x+3y=1 求3x²+12xy+12y²的值
x+3y-x-y=2y=0.8 y=0.4 x=-0.2 原式=3（x+2y）*（x+2y）=3*0.6*0.6=1.08

x+y=0.2 x+3y=1
2x+4y=1.2
x+2y=0.6
3x²+12xy+12y²
=3(x+2y)^2
=3*0.6^2
=1.08

3x²+12xy+12y²=3（x+2y）²=3*0.6²=1.08