2x^(1/3)[1/2x^(1/3)-2x^(-2/3)]要解法上面的题错了2x^(-1/3)[1/2x^(1/3)-2x^(-2/3)]

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2x^(1/3)[1/2x^(1/3)-2x^(-2/3)]要解法上面的题错了2x^(-1/3)[1/2x^(1/3)-2x^(-2/3)]
2x^(1/3)[1/2x^(1/3)-2x^(-2/3)]要解法
上面的题错了2x^(-1/3)[1/2x^(1/3)-2x^(-2/3)]

2x^(1/3)[1/2x^(1/3)-2x^(-2/3)]要解法上面的题错了2x^(-1/3)[1/2x^(1/3)-2x^(-2/3)]
2x^(-1/3)[1/2x^(1/3)-2x^(-2/3)]=x^(-1/3+1/3)-4(x^(-1/3-2/3))=x^0-4x^(-1)=1-4/x=(x-4)/x

你 要解什么啊?这就一代数式啊!

2x^(1/3)[1/2x^(1/3)-2x^(-2/3)]=x^(2/3)-4 x^(-1/3)=x^(-1/3)(x-4)

就直接化简就行,得到:1-4*X.....这个不是等式,怎么解?
假设1-4*X=a
解得x=(1-a)/4

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