36(x-2)(x-2)-49(x+1)(x+1)=0 (2x-3)(2x-3)=3-2x 要这两道题的具体步骤.

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/16 16:36:39

36(x-2)(x-2)-49(x+1)(x+1)=0 (2x-3)(2x-3)=3-2x 要这两道题的具体步骤.
36(x-2)(x-2)-49(x+1)(x+1)=0 (2x-3)(2x-3)=3-2x 要这两道题的具体步骤.

36(x-2)(x-2)-49(x+1)(x+1)=0 (2x-3)(2x-3)=3-2x 要这两道题的具体步骤.
[6(x-2)]^2-[7(x+1)]^2=0
6(x-2)=7(x+1)
x=-19

4x^2-12x+9=3-2x
4x^2-10x-6=0
2x^2-5x-3=0
x=3 or x=-1/2

36(x-2)^2=49(x+1)^2
(x-2)^2/(x-1)^2=49/36
(x-2)/(x-1)=7/6或-7/6
x=-19 x=5/13
(2)方程可化为2x^2-5x+3=0
即(2x-3)(x-1)=0
x=3/2 x=1

36(x-2)(x-2)-49(x+1)(x+1)=0
[6(x-2) +7(x+1)] [6(x-2) -7(x+1)] =0
(13x-5) (-x-19)=0
x1=5/13, x2=-19
(2x-3)(2x-3)=3-2x
(2x-3)^2 + (2x-3) =0
(2x-3) (2x-3+1)=0
x1=3/2 , x2= 1
【俊狼猎英】团队为您解答