1/3(5y+1)+(1/3-1/3y)=(3y-1/3)-(y+1/3) y=?
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1/3(5y+1)+(1/3-1/3y)=(3y-1/3)-(y+1/3) y=?
1/3(5y+1)+(1/3-1/3y)=(3y-1/3)-(y+1/3) y=?
1/3(5y+1)+(1/3-1/3y)=(3y-1/3)-(y+1/3) y=?
方程两边乘以3
5y+1+1-y=9y-1-3y-1
4=2y
y=2
.............y=2
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y (3y^2+8y-3)-6y(3y+2y-1)+9y
2(y-4)(3y+2)-5(-3y+7)(y+1),其中y=-1
解方程:3y^2-(2y+1)(y-1)=(y-5)(y+1)
5y∧2-(y-2)(3y+1)-2(y+1)(y-5)
解方程3y^2-(2y+1)(y-2)=(y-5)(y-1)
解方程:3y²-(2y+1)(y-2)=(y-5)(y+1)
(y+3)(4y-1)
通分 y+3/y*y-6y+9,1/2y+6,y-1/y*y-9
3(y-3)-5(1+y)=7(y-1)
y-(y-1)/2=1-(2y-3)/5
解方程y-[3y-1]等于5【y+2]
y''-5y'+6y=3x+1通解
y-y-1/2=3-y+2/5
计算:[(y+1)/(y^2-4y+3)减去(y-2)/(y^2-6y+9)]除以(y-5)/(y-1)
y-1/y-2 - y-3/y-4=y-2/y-3 - y-4/y-5一共有四个分数哦~希望可以快一点~谢谢!