【x-1】²-2【x²-1】=0用因式分解法

【x-1】²-2【x²-1】=0用因式分解法
【x-1】²-2【x²-1】=0用因式分解法

【x-1】²-2【x²-1】=0用因式分解法
( x - 1 )" - 2( x" - 1 ) = 0
( x - 1 )" - 2( x + 1 )( x - 1 ) = 0
( x - 1 )[ ( x - 1 ) - ( 2x + 2 ) ] = 0
( x - 1 )( x - 1 - 2x - 2 ) = 0
( x - 1 )( -x - 3 ) = 0
( x - 1 )( x + 3 ) = 0
解方程得
x1 = 1
x2 = -3