已知复数z是纯虚数,z+1/1-i是实数,则z=

已知复数z是纯虚数,z+1/1-i是实数,则z=
已知复数z是纯虚数,z+1/1-i是实数,则z=

已知复数z是纯虚数,z+1/1-i是实数,则z=
设z=ai a为实数
ai+1/(1-i)
=ai+(1+i)/((1+i)(1-i))
=ai+1/2+i/2
=1/2+(a+1/2)i
其为实数,则a+1/2=0.a=1/2
z=1/2i

设z=ai a为实数
ai+1/(1-i)
=ai+(1+i)/((1+i)(1-i))
=ai+1/2+i/2
=1/2+(a+1/2)i
其为实数,则a+1/2=0.a=1/2
z=1/2i

-i