若3sina+cosa=0,则1/sin^2a+cos^2a= A.10/3 B.5/3 C.2/3 D.-2

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若3sina+cosa=0,则1/sin^2a+cos^2a= A.10/3 B.5/3 C.2/3 D.-2
若3sina+cosa=0,则1/sin^2a+cos^2a= A.10/3 B.5/3 C.2/3 D.-2

若3sina+cosa=0,则1/sin^2a+cos^2a= A.10/3 B.5/3 C.2/3 D.-2
3sinA+cosA = 0
tanA = -1/3
(sinA)^2 = 1/10
(cosA)^2 = 9/10
1/(sinA)^2 + (cosA)^2
= 10+9/10
=109/10

(sina)^2+(cosa)^2=1
(sina)^2+9(sina)^2=1
(sina)^2=1/10
(cosa)^2=9/10
1/sin^2a+cos^2a=1/(1/10)+9/10=10+9/10=10.9

3sina+cosa=0,则tana=-1/3

所以sin^2a=1/10
cos^2a=9/10
所以A=10+0.9=10.9
答案不对还是题目不对?

3sina+cosa=0→tana=-1/3
万能公式算出:sin2a=-3/5,cos2a=4/5
1/sin^2a+cos^2a=2/(1-cos2a)+(1+cos2a)/2

tana=-1/3,tan2a=-3/4
1+1/tan^2a+(c^2-s^2)/(c^2+s^2)