若1/x :1/y :1/z =4:5:6 ,使x+y+z=74成立的y值是( )24请主要描述一下解题思路、过程,
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/07 16:33:40
若1/x :1/y :1/z =4:5:6 ,使x+y+z=74成立的y值是( )24请主要描述一下解题思路、过程,
若1/x :1/y :1/z =4:5:6 ,使x+y+z=74成立的y值是( )
24
请主要描述一下解题思路、过程,
若1/x :1/y :1/z =4:5:6 ,使x+y+z=74成立的y值是( )24请主要描述一下解题思路、过程,
1/x :1/y :1/z =4:5:6
设1/x=4/k,1/y=5/k,1/z=6/k
即x=k/4,y=k/5,z=k/6
又x+y+z=74
∴k/4+k/5+k/6=74
∴k=120
∴y=120/5=24
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
三元一次方程组题目x+y-z=11 y+z-x=5 x-y+z=1x+y=4 y+z=3 x+z=5若已知x-3y+2z=0 2x+3y-8z=0, 且xyz≠0,则x:y:z=
{x+y-z=11 y+z-x=5 z+x-y=1
{x+y-z=11,x-y-z=-5,x-y+z=1
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
5x+y+z=1 2x-y+2z=1 x+5y-z=4
若实数XYZ满足2|x-y|+√2y+z+z方-z+1//4=0 求X+Y+Z 2y+z在根号里
解方程x-y+4z=5,y-z+4x=-1,z-x-4y=4
x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5
3x-y+2z=-1 4x+y+z=5 x-2y-z=-2
x+y+z=-1 4x-2y+3z=5 y-z=8-2x
x+y+z=1 4x+5y-z=6 x+2y-z=3
x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快
{x+y+z=1 {x+3y+7z=2 {x+5y+19z=4
若x:y:z=1:3:5,求分式x+3y-z/x-3y+z的值
若x:y:z=1:3:5,求x+3y-z/x-3y+Z的值.
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
x,y,z属于正实数,且3x+4y+5z=1 求1/(x+y)+1/(y+z)+1/(x+z)的最小值