(√6x +2√x-1 )(√6x - 2√x-1 ) (√表示算术平方根) 把它化简
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(√6x +2√x-1 )(√6x - 2√x-1 ) (√表示算术平方根) 把它化简
(√6x +2√x-1 )(√6x - 2√x-1 ) (√表示算术平方根) 把它化简
(√6x +2√x-1 )(√6x - 2√x-1 ) (√表示算术平方根) 把它化简
(√6x +2√x-1 )(√6x - 2√x-1 )
=[√(6x)]^2-2^2*[√(x-1)]^2
=6x-4(x-1)
=6x-4x+4
=2x+4
主要是根号到哪里
(A+B)*(A-B)=A^2-B^2
(√6x +2√x-1 )(√6x - 2√x-1 )
=[(√6x )^2- (2√x-1 )^2]
=|6x|-4*|x-1|
当x>=1时
原式=6x-4x+4
=2x+4
当0<=x<1
原式=6x-4+4x
=10x-4
当x<0
原式=-6x-4+4x
=-2x-4
平方差公式也。。。
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