x=0,1,2时y=1,0.5,0.2.求分段线性插值函数
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x=0,1,2时y=1,0.5,0.2.求分段线性插值函数
x=0,1,2时y=1,0.5,0.2.求分段线性插值函数
x=0,1,2时y=1,0.5,0.2.求分段线性插值函数
由已知可设该二次函数为:Y=aX^2+bX+c.
1.当X=0时,Y=-1可得:c=-1.
2.当X=-2时,Y=-1可得:4a-2b-1=0.(1)
当X=0.5时,Y=-1可得:a+2b-4=0.(2)
联立(1)、(2)方程解得:a=1,b=3/2.
所以该二次函数为:Y=X^2+(3/2)X-1.
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