已知sin(α-π/3)=1/3,则cos(π/6+α)=

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已知sin(α-π/3)=1/3,则cos(π/6+α)=
已知sin(α-π/3)=1/3,则cos(π/6+α)=

已知sin(α-π/3)=1/3,则cos(π/6+α)=
cos(π/6+α)=cos(π/2+(α-π/3))=-sin(α-π/3)=-1/3