|x+y+4|+(x-2）²=0则3z+2y=

|x+y+4|+(x-2）²=0则3z+2y=
|x+y+4|+(x-2）²=0则3z+2y=

|x+y+4|+(x-2）²=0则3z+2y=
|x+y+4|+(x-2）²=0
则：
x+y+4=0
x-2=0
解得：
x=2；y=-6
3x+2y=6-12=-6

|x+y+4|+(x-2）²=0
则x+y=-4 x=2
∴y=-6
∴3x+2y=6-12=-6

因为绝对值和平方都是正数，所以x+y=-4，x=2