｛an｝满足a1=3a(a>0),a(n+1)=(an的平方+a的平方)/2an,设bn=(an-a)/(an+a),1．求数列｛bn｝的通项公式问题 2．设数列｛bn｝的前项和为sn 比较sn与7／8的大小

数列[An]满足a1=2,a（n+1）=3an-2 求an 数列{An}满足A1=1,A(n+3)=An+3,A（n+2)=An +2 数列An满足A1=0,A(n+1)=(An-√3)/(√3An+1)则A2009= 数列{an)满足an=4a(n-1)+3,a1=0,求数列{an}的通项公式 已知数列{an}满足an>0,a1=3 根号下[a(n+1)]=(根号下an)+1 （n属于N*) 则an=?如题. 数列｛an｝满足a1=3,a n+1=2an,则a4等于 已知数列{an}满足a1=1,3a(n+1)+an-7 已知数列{an}满足a(n+1)=an+n,a1=1,则an= 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 已知数列{an}满足a1=1,a2=3,a(n+2)=a(n+1)-an,求S2012 已知数列｛an｝满足a(n+1)=an+3n+2,且a1=2,求an=? 在数列an中,a1=1,且满足a（n+1）=3an +2n,求an 已知等差数列{an}满足a(n+1)=an+3n+2,且a1=2,求an.雪地跪拜! 已知数列an满足a(n+1)=an+3n+2,且a1=2,求an 已知数列an满足a1=1,a(n+1)=an/(3an+2),则an=? 已知数列{an}满足条件a1=3,且a( n+1)-an=(20)^n+n,求通项公式已知数列{an}满足条件a1=3,且a( n+1)-an=(2)^n+n,求通项公式 根据下列条件,确定数列{an}的通项公式1.在数列｛an｝中,a(n+1)=3an^2,a1=32.在数列｛an｝中,a1=2,a(n+1)=4an-3n+13.在数列｛an｝中,a1=8,a2=2,且满足a(n+2)-4a(n+1)+3an=0 已知数列{an}满足a1=0 a(n+1)=(an-根号3）/(根号3an+1) (n属于N*）,则a20=?