x+2y-z=12 x/2=y/3+z/2=k 求k值x+2y-z=12,且x/2=y/3+z/2=k 求k值
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x+2y-z=12 x/2=y/3+z/2=k 求k值x+2y-z=12,且x/2=y/3+z/2=k 求k值
x+2y-z=12 x/2=y/3+z/2=k 求k值
x+2y-z=12,且x/2=y/3+z/2=k 求k值
x+2y-z=12 x/2=y/3+z/2=k 求k值x+2y-z=12,且x/2=y/3+z/2=k 求k值
12 x/2?
x+y=2k (1)
y+z=3k (2)
z-2x=4k (3)
(1)-(2)
x-z=-k (4)
(3)+(4)
-x=3k
x=-3k
y=2k-x=5k
z=3k-y=-2k
所以-3k+10k+2k=9
k=1
∵x/2=y/3=z/2=k
∴x=2k y=3k z=2k
∵x+2y-z=12
∴2k+6k-2k=12
∴k=2
X/2=Y/3=Z/4=K
则
x=2k
y=3k
z=4k
x+2y-z=12
2k+6k-4k=12
4k=12
k=3
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