求lim n→∞(1/n^2 + 2/n^2 +...+ n/n^2 )=lim n→∞ 1+2+...+n/n^2=lim n→∞ (1+n)n / 2n^2 这一步怎么来的?=1/2 lim n→∞(1+1/n) 这一步怎么来的?=1/2

求lim n→∞ (1+2/n)^n+3 求极限lim [ 2^(n+1)+3^(n+1)]/2^n+3^n (n→∞) lim n →∞ (1^n+3^n+2^n)^1/n,求数列极限 求极限lim(x→∞)（1/n+2/n+3/n..+n/n） 用夹逼定理求lim(n→∞)[√(n^2+n)-n]^(1/n) 求极限lim(n→∞)(1/n²+2/n²+...+n/n²) 用夹逼定理求lim(n→∞)√[(n^2+n)-n]^(1/n) 求lim n→+∞(1/n^k+2/n^k+ +n/n^k)有三种情况, 求极限n~∞,lim(n+1)/2n 求极限lim n→∞(1/(n+1)+1/(n+2)+.+1/(n+n) 求极限(1/(n+1)+1/(n+2)+.+1/(n+n) 求lim(n→∞)(3n^3+2n^2+1)/(2n^2+3) 求极限lim(n→∞)(3n^2-n+1)/(2+n^2)? 求极限lim(-2)^n+3^n/(-2)^[n+1]+3^[n+1] (x→∞) lim（1/n+2^1/n）^n n→∞求详解!高数极限 求当n→∞,Lim(1+2+3+4+……+(n-1)+n)/n lim(n→∞) 1/(n+1)-2/(n+1)+3/(n+1)-4/(n+1)+...+[(2n-1)/(n+1)]-[(2n)/(n-1)]求极限 求极限 lim(n→∞) (ln(1+1/n)/(n+1)+ln(1+2/n)/(n+2)+...+ln(1+n/n)/(n+n)) 求极限 lim(n→∞) tan^n (π/4 + 2/n) lim(n→∞)tan^n(π/4+2/n) =lim(n→∞)[(tan(π/4)+tan(2/n))/(1-tan(π/4)tan(2/n))]^n =lim(n→∞)[(1+tan(2/n))/(1-tan(2/n))]^n =lim(n→∞)(1+tan(2/n))^n/(1-tan(2/n))^n (1) 因为 lim(n→∞)(1+tan(2/n)