以知sin(a+b)sin(a-b)=-1/3 求cosa的平方减去cosb的平方的值
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以知sin(a+b)sin(a-b)=-1/3 求cosa的平方减去cosb的平方的值
以知sin(a+b)sin(a-b)=-1/3 求cosa的平方减去cosb的平方的值
以知sin(a+b)sin(a-b)=-1/3 求cosa的平方减去cosb的平方的值
sin(a+b)sin(a-b)=-1/3
(sina*cosb+cosa*sinb)(sina*cosb-cosa*sinb)=-1/3
cos^2 a*sin^2 b-sin^2 a*cos^2 b=1/3
(cos^2 a)(1-cos^2 b)-(1-cos^2 a)cos^2 b=1/3
cos^2 a -cos^2 b=/13
cosa的平方减去cosb的平方的值为1/3
sin(a+b)sin(a-b)
=-1/2*[cos2a-cos2b]
=-1/3
cos2a-cos2b=2/3
2cos^2 a-1-(2cos^2b-1)=2/3
2(cos^2 a-cos^2 b)=2/3
cos^2 a-cos^2 b=1/3
证明sin(a+b)sin(a-b)=sin^2 a-sin^2 b,
如何证明sin(a+b)sin(a-b)=sin*a-sin*b (*为平方)
求证恒等式sin(A+B)sin(A-B)=sin²A-sin²B
求证:sin(a+b)sin(a-b)=sin^2a-sin^2b
sin a-sin b等于
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sin(a+b)sin(a-b)=sin2a-sin2b求证
求证:sin(A+B)sin(A-B)=sinAsinA-sinBsinB
sin(a-b)=sin(a+b)吗?
SIN(B-A)=-SIN(A-B)为啥
求 sin(a+b)=?
sin(a-b)=?
证明sina sin(a+2b) - sinb sin(b+2a) =sin(a+b)sin(a-b)
懂得进.证明,sina+sin(a+b)+sin(a+2b)+...sin(a+nb)=sin(a+ab/2)sin[(n+1)b/2]/sin(b/2)
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证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2B=1