|x-2|+√x-2y+z^2-2z+1=0,求3x-y+z的值
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|x-2|+√x-2y+z^2-2z+1=0,求3x-y+z的值
|x-2|+√x-2y+z^2-2z+1=0,求3x-y+z的值
|x-2|+√x-2y+z^2-2z+1=0,求3x-y+z的值
|x-2|+√x-2y+z^2-2z+1=|x-2|+√x-2y+(z-1)^2=0
上式若成立必须有:
x-2=0
x-2y=0
z-1=0
x=2,y=1,z=1
所以3x-y+z=6-1+1=6
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