x的2n次方-y的2n次方\x的n次方+y的n次方等于
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x的2n次方-y的2n次方\x的n次方+y的n次方等于
x的2n次方-y的2n次方\x的n次方+y的n次方等于
x的2n次方-y的2n次方\x的n次方+y的n次方等于
[x^(2n)-y^(2n)]/[x^(n)+y^(n)]
=(x^n-y^n)*(x^n+y^n)/(x^n+y^n)
= x^n-y^n
=(x的n次方+y的n次方)(x的n次方-y的n次方)/(x的n次方+y的n次方)
=x的n次方-y的n次方