y=(3x-1)/(x+1) (x>=5)值域 y=x-√(1-2x)值域
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y=(3x-1)/(x+1) (x>=5)值域 y=x-√(1-2x)值域
y=(3x-1)/(x+1) (x>=5)值域 y=x-√(1-2x)值域
y=(3x-1)/(x+1) (x>=5)值域 y=x-√(1-2x)值域
1.分离变量.Y∈[7/3,3)
2.设t=根号(1-2x).Y∈(负无穷,0.5]
1.y=3-4/(x+1),由于x>=5,所以 y>=7/3
2. 用deta 法算 y<=1
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
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{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
(2x+y-1)(2x-y+1)-(3x+y)(3x-y),其中x=5分之1,
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y=3x-1/x+1(x>=5)
5(x-y)³-3(x-y)²+7(x-y)-5(x-y)³+(x-y)²-5(x-y),其中,x-y=1/3.5(x-y)³-3(x-y)²+7(x-y)-5(x-y)³+(x-y)²-5(x-y),其中,x-y=1/3先化简,再求值;
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{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
x=3,y=-x+5(x>1) y=-x+5(x≤1),y=?
化简 求值 x-{-5x-[-y+(-x+3y)+x]},其中x=-1,y=-2;